Choose unique values for the 'webAppRootKey' context-param in your web.xml files!

Sovled this err by using
 Add this in web.xml file
<context-param>
<param-name>WEBAPPROOTKEY</param-name>
<param-value> Unique ID </param-value>
</context-param>

 

 For this kind of error

java.lang.IllegalStateException: Web app root system property already set to different value: 'webapp.root' = ....... instead of .....................- Choose unique values for the 'webAppRootKey' context-param in your web.xml files!
    at org.springframework.web.util.WebUtils.setWebAppRootSystemProperty(WebUtils.java:144)
    at org.springframework.web.util.Log4jWebConfigurer.initLogging(Log4jWebConfigurer.java:117)
    at org.springframework.web.util.Log4jConfigListener.contextInitialized(Log4jConfigListener.java:45)
    at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4723)
    at org.apache.catalina.core.StandardContext$1.call(StandardContext.java:5226)
    at org.apache.catalina.core.StandardContext$1.call(StandardContext.java:5221)
    at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:303)
    at java.util.concurrent.FutureTask.run(FutureTask.java:138)
    at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908)
    at java.lang.Thread.run(Thread.java:662)